/* The program creates a child process and waits for it to finish. If a timeout
* elapses the child is killed. Waiting is done using sigtimedwait(). Race
* condition is avoided by blocking the SIGCHLD signal before fork().
*/
#include <sys/types.h>
#include <sys/wait.h>
#include <signal.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <errno.h>
static pid_t fork_child (void)
{
int p = fork ();
if (p == -1) {
perror ("fork");
exit (1);
}
if (p == 0) {
puts ("child: sleeping...");
sleep (10);
puts ("child: exiting");
exit (0);
}
return p;
}
int main (int argc, char *argv[])
{
sigset_t mask;
sigset_t orig_mask;
struct timespec timeout;
pid_t pid;
sigemptyset (&mask);
sigaddset (&mask, SIGCHLD);
if (sigprocmask(SIG_BLOCK, &mask, &orig_mask) < 0) {
perror ("sigprocmask");
return 1;
}
pid = fork_child ();
timeout.tv_sec = 5;
timeout.tv_nsec = 0;
do {
if (sigtimedwait(&mask, NULL, &timeout) < 0) {
if (errno == EINTR) {
/* Interrupted by a signal other than SIGCHLD. */
continue;
}
else if (errno == EAGAIN) {
printf ("Timeout, killing child\n");
kill (pid, SIGKILL);
}
else {
perror ("sigtimedwait");
return 1;
}
}
break;
} while (1);
if (waitpid(pid, NULL, 0) < 0) {
perror ("waitpid");
return 1;
}
return 0;
}
Comments
if you receive EINTR, would
You're right. Some system